Codes here !

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New php-forum User
New php-forum User
Posts: 191
Joined: Wed Jan 29, 2003 7:11 am
Location: UK

Sun Feb 16, 2003 2:28 am

it means the argument ($var) you set within the function call is not returning a resource that the script can read

remember mysql_num_rows is only for inserts and the link identifier should reference the mysql_query rather than the mysql_fetch_array/??

if everything else seems fine, try slinging an
echo mysql_error();
after your query line.
avatar image based upon nasas apod (only updates if I post though)

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