Board index   FAQ   Search  
Register  Login
Board index php forum :: Database mySQL & php coding

Distance calculation based on multiple locations (Lat,Lon)

Codes here !

Moderators: macek, egami, gesf

Distance calculation based on multiple locations (Lat,Lon)

Postby nitapita » Thu May 09, 2013 10:48 pm

0 down vote favorite


I would like to calculate the total distance of driving beetween multiple locations (loop), including the distance (starting point (garage) - first location sarting point) and (last location finishig point - finishing point (garage)). Example: (Garage + D1) + (D1 + D2) + (D2 + E1) + (E1 + E2) + E2 + Garage)

I'm having a problem with the correct looping. Here's my simplified code:

Code: Select all
<?
$driver = 5;

     $result2 = mysql_query("SELECT * FROM test WHERE id='$driver' LIMIT 1") or die(mysql_error());
     while($row2 = mysql_fetch_array( $result2 )) {
         $lon=$row2['lon'];
         $lat=$row2['lat'];
    echo "$lon, $lat";
     }

   $result = mysql_query("SELECT * FROM test1 WHERE driver='$driver'") or die(mysql_error()); 
    while($row = mysql_fetch_array( $result )) {

         $lon1=$row['lon1'];
         $lat1=$row['lat1'];
         $lon2=$row['lon2'];
         $lat2=$row['lat2'];

        //////////  distance between driver address and starting address   
        $distancecalc = (3958*3.1415926*sqrt(($lat-$lat1)*($lat-$lat1) + cos($lat/57.29578)*cos($lat1/57.29578)*($lon-$lon1)*($lon-$lon1))/180);
        //////////  distance between statring address and finishing address  - multiple adsresses
        $distancecalc1 = $distancecalc1 + (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180);
        //////////  distance between finishing address and driver address
        $distancecalc2 = (3958*3.1415926*sqrt(($lat2-$lat)*($lat2-$lat) + cos($lat2/57.29578)*cos($lat/57.29578)*($lon2-$lon)*($lon2-$lon))/180);

        $distancetotal = $distancecalc + $distancecalc1 +$distancecalc2;

        echo "$distancecalc<br>
        $distancecalc1<br>
        $distancecalc2<br>";
    }
    echo "$distancetotal";
  ?>


I'm aware that code posted above doesnt't do what it meant to .. i just want to keep it clear.. there is some things i tried but no correct resoults.

I would appreciate some help on this one.

Thank you very much.
nitapita
New php-forum User
New php-forum User
 
Posts: 8
Joined: Sun Jan 06, 2013 12:41 am

Re: Distance calculation based on multiple locations (Lat,Lo

Postby nitapita » Fri May 10, 2013 3:32 am

Ok. I worked it out with help of mac_gyver (php freaks). All calculations are done as i wish. My code below:

Code: Select all
<?
include "connectdb.php";
$driver = 5;
$datestamp = '2013/05/07';
$result2 = mysql_query("SELECT * FROM drivers WHERE id='$driver' LIMIT 1") or die(mysql_error());
while($row2 = mysql_fetch_array( $result2 )) {
$lon=$row2['lon'];
$lat=$row2['lat'];
}

$result = mysql_query("SELECT * FROM quotedb WHERE moveday='$datestamp' AND driver='$driver' AND cleared='Not Cleared' AND status='Done' ORDER BY moveday, timeday") or die(mysql_error());
$distance = 0; // accumulate the distance
$first_pass = true; // flag to detect the first row inside the loop
while($row = mysql_fetch_assoc( $result )) {
$lon2a=$lon2;
$lat2a=$lat2;
$lon1=$row['lon1'];
$lat1=$row['lat1'];
$lon2=$row['lon2'];
$lat2=$row['lat2'];
// calculate the distance from the Garage to the first point of the first row
if($first_pass){
$distance += (3958*3.1415926*sqrt(($lat-$lat1)*($lat-$lat1) + cos($lat/57.29578)*cos($lat1/57.29578)*($lon-$lon1)*($lon-$lon1))/180);
$first_pass = false;
}
// calculate the distance for each row (segment) in the route
$distance += (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180);
if ( $lon2a == "" and $lat2a =="" ) {
} else {
// calculate the distance from the second point of the first row to the first point of the next row
$distance += (3958*3.1415926*sqrt(($lat2a-$lat1)*($lat2a-$lat1) + cos($lat2a/57.29578)*cos($lat1/57.29578)*($lon2a-$lon1)*($lon2a-$lon1))/180);
}
}
// calculate the distance from the second point of the last row to the Garage
$distance += (3958*3.1415926*sqrt(($lat2-$lat)*($lat2-$lat) + cos($lat2/57.29578)*cos($lat/57.29578)*($lon2-$lon)*($lon2-$lon))/180);
echo "$distance<br>
";
?>


Still think there is a place for improvement in the code. Will aplay Haversine method for calculations. Do you guys have some suggestion to improve this piece of code ... thx
nitapita
New php-forum User
New php-forum User
 
Posts: 8
Joined: Sun Jan 06, 2013 12:41 am


Return to mySQL & php coding

Who is online

Users browsing this forum: Google [Bot] and 1 guest

Sponsored by Sitebuilder Web hosting and Traduzioni Italiano Rumeno and antispam for cPanel.