dropdown list doubt

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Joined: Mon May 21, 2012 2:14 am

dropdown list doubt

Postby actuallypb » Mon May 21, 2012 3:12 am

I'm using following script to display dropdown list :

$SQL2 = "SELECT circle_name FROM circleinfo WHERE company_name= $sess";
$result2 = mysql_query($SQL2);
echo '<label>Select username:</label>';
echo '<select name="circlename">';
echo '<option value="">Select</option>';

while ($row = mysql_fetch_assoc($result2))
$va = $row['circle_name'];
echo "<option value='$va'>$va</option>";
echo '</select>';

now my doubt is, how do i retrieve selected value from dropdown list?? when I use $_POST['circlename']; I get an error. when I use if ($_SERVER['REQUEST_METHOD'] == 'POST') then dropdown list doesnt get displayed. please help. thank you.

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Re: dropdown list doubt

Postby macek » Mon May 21, 2012 10:48 am

Code: Select all

echo "<option value='$va'";
if(isset($_POST['circlename']) && $_POST['circlename'] == $va) echo ' selected="selected"';
echo ">$va</option>";

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