Probably A Simple Answer

[kingk]

I am a complete newbie to PHP and MySQL but I am trying to learn. I am trying to figure out how to keep all of the info in my table from displaying. Here is my example:
Here is the link I would give:

http://www.hightidemedia.net/v7/clientid.php?id=obh

But if i just type in
http://www.hightidemedia.net/v7/clientid.php
It lists all of the info in the table. How do I keep this from happening?

Here is the code I use to query the database:

<?php

mysql_connect (localhost, ******, ********);

mysql_select_db (******);

if ($id == "")
{$id = '%';}


$result = mysql_query ("SELECT * FROM client
WHERE id LIKE '%$id%'
");

if ($row = mysql_fetch_array($result)) {

do {
Print $row["company"];
print (" ");
print ("<br>");
print ("<p>");
print $row["pic"];
print ("<p>");
print $row["url"];
print ("<br>");

} while($row = mysql_fetch_array($result));
} else {print "Oops! Either I made a mistake, or you did!";}


?>

[DoppyNL]

Code: Select all

if ($id == "")
{$id = '%';}

You find out here that id is not supplied to the script.
You give it a value so that any value in the database will be returned.
You could also give it some default value or give an error message and exit you're script.

Greetz Daan

[kingk]

ID is one of the colomns in my table. So what can I add to that statement so that if nothing is put in as the "ID" it will display nothing?

I want http://www.hightidemedia.net/v7/clientid.php to be blank.

[DoppyNL]

LIKE "%" will allow ANY value, so if ID is not present it will allow any value.
You could check if ID is supplied to you're script and if it is not remove the %%.
LIKE is used for string-comparison.

Also, if you're trying to select a specific item you could better use:

Code: Select all

where id = 12

, or when you want a range:

Code: Select all

where id > 12 and id <40

It will execute faster.
The speed will not really be noticed on small tables, but the moment they get much bigger you'll notice the difference.

Greetz Daan