piece of a variable

[Xerpher]

How would I see if $var has "access" in the beginning of it?

[Jay]

What are you looking for?

1. A variable who's name starts with 'access'?

Code: Select all

while(list($var,$val) = each($GLOBALS)) {
if (preg_match('^access'),$var) {
$theValue = $var;
break;
}
}


2. A variable which has access as the beginning of it's string value?

Code: Select all

while(list($var,$val) = each($GLOBALS)) {
if (preg_match('^access'),$val) {
$theValue = $var;
break;
}
}


3. Anything else? Can you see a pattern forming?

[Xerpher]

Thanks, its #2 I need

[Jay]

OK, but the correct code should have been

Code: Select all

while(list($var,$val) = each($GLOBALS)) {
if (preg_match('^access'),$val) {
$theValue = $val;
break;
}
}


I put $theValue = $var instead of $val, but you would have figured that part out, wouldn't you ;)

[Xerpher]

Lol, well that explains why it didn't work you fixed it before I even said it didn't work

[Jay]

Well, let me know if it works, because I made up that REGEX up on the spot, and it's definately not my strong point. I just happen to know that the ^ character means at the beginning!

[Xerpher]

It worked.... I just ad to fix two tny things

Code: Select all

while(list($var,$val) = each($_GET)) {
   if (preg_match('^access^',$val)) {
      $theValue = $val;
      break;
   }
}


See, I had to move the ')' to after the $val, and had to put another '^' at the nd of access. But still thanks, I've never used preg_match before so would've had no idea about those symbols and which ones to use.

[Jay]

Ah yes true, how could I have been so daft to leave out the $val out of the function! Not sure why you'd need to add a second ^ though, because that means at the beginning, so it's only good once. But if it works, all is well