FOR LOOP

[miguelna]

wat's wrong with the following code? I want change the values at right of the x and y. $x1, $x2, $x3.... and $ponto1[2], $ponto2[2], $ponto3[2]...
I tried $x$i

Help!!!

Code: Select all

<? for ($i = 1; $i < 23; $i++) {
?>
<area shape="rect" coords="<? echo $x$i.",".$y$i.",".($x$i+10).",".($y$i+10) ?>" href="<? echo "$PHP_SELF?a_cor=1"; ?>" alt="<? echo $ponto$i[2] ?>">
<?
}
?>


Thanks
Miguel

[elitecodex]

Are you getting any errors? I do noticed that you missed some semi-colon's on the end of your echo statements. Try appending those and see what happens.

[miguelna]

my code is:

Code: Select all

<? for ($i = 1; $i < 23; $i++) {
?>
<area shape="rect" coords="<? echo $x.$i.",".$y.$i.",".($x.$i+10).",".($y.$i+10) ?>" href="<? echo "$PHP_SELF?a_cor=1"; ?>" alt="<? echo $ponto.$i[2] ?>">
<?
}
?>


[elitecodex]

ok, so change it to this:

Code: Select all

<? for ($i = 1; $i < 23; $i++) {
?>
<area shape="rect" coords="<? echo $x.$i.",".$y.$i.",".($x.$i+10).",".($y.$i+10); ?>" href="<? echo "$PHP_SELF?a_cor=1"; ?>" alt="<? echo $ponto.$i[2]; ?>">
<?
}
?>


and if $ponto is an array, why are you accessing it like "$ponto.$i[2]" ? Im confused on what your trying to do.

[miguelna]

I have some arrays $ponto1, $ponto2,… and I want print the field [2] of the array. My problem is concatenate $ponto with $i to generate the desired name for link to the array.

The same for x. I want a script to increase the value in the right of x, to $x1, $x2, $x3…

[Jay]

Err, are you looking to use $x[$i] instead of $x$i ??