can´t see the image

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can´t see the image

Postby malpolon » Thu May 12, 2011 12:22 pm

Dear PHP-Programmer,

I have a PHP script which select randomly a image from a folder called" bilder", the script has the name sabine3.php and it is the following:


function getRandomImage($dir,$type='random')
global $errors,$seed;

if (is_dir($dir)) {

$fd = opendir($dir);
$images = array();

while (($part = @readdir($fd)) == true) {

if ( eregi("(gif|jpg|png|jpeg)$",$part) ) {
$images[] = $part;

// adding this in case you want to return the image array
if ($type == 'all') return $images;

if ($seed !== true) {
mt_srand ((double) microtime() * 1000000);
$seed = true;

$key = mt_rand (0,sizeof($images)-1);

return $dir . $images[$key];

} else {
$errors[] = $dir.' is not a directory';
return false;

$image = getRandomImage('bilder/');

echo "<img src='$image' alt='Random Image' border=\"0\">";


The script is OK but I want to create a HTM-page where I can show the random image, I wrote this HTM-Code:

<html xmlns="">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style type="text/css">
body {
background-color: #99CC33;
<img src="<? sabine3.php ?>" alt="sabine" />

But it doesn´t work, so how can I show the image???

Thank you,


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Re: can´t see the image

Postby egami » Mon May 16, 2011 8:37 am


Your function returns a picture *IF* it's successful.
What happens when you run the php directly?

ie.. ?

Ich hoffe das du nicht im Wiesau wohnst.. Ich konte mir nicht glauben das die Sabine das Ich kenne wird sich bilder auf der Internet lassen.

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